Regex replace escape $

Trying to get -replace to escape the first $ in this statement: ‘TRUE’ -replace ‘(TRUE|FALSE)’,’$$1’

Have tried , and ` with no luck. It just outputs $1 each time.

Thoughts?

Are you trying to replace ‘TRUE’ with ‘$TRUE’? If so, you need one more $ in your string. (The first two $$ are a literal $ in the output, and then $1 is the replacement token).

As a bonus, here’s how you’d update your pattern to only inject the dollar sign if it wasn’t already there: https://gist.github.com/dlwyatt/b846add5b5cacefc2409

Edit: Moved code over to a gist, the forum was converting some of my single-quotes to double for some weird reason.

Thanks just tried that lol.