Function parameters not working

PowerShell Help
1

Sorry if this has been covered in the forum …

take the following function

Function test ($val1, $Val2)
{
Write-Host $Val1

}

If I call the function : test(“one”,“two”) , I get output of one two , and not One only , it would seem that parameter two does not get populated , but parameter 1 ($val1) receives both values …

what am I missing … ?

2

PowerShell functions are called with parameters / arguments separated by spaces, not commas. There are also not any parentheses around the parameter list in the function call.

(“one”, “two”) is actually an array which is bound to a single parameter, as you’ve seen. With your function definition as-is (with two optional parameters that can both be passed by either name or position), here are the legal ways you could call it:

# no parameters
test

# two parameters by name
test -Val1 "one" -Val2 "two"

# two parameters by position
test "one" "two"

# One parameter by name (either one)
test -Val1 "one"
test -Val2 "two"

# One parameter by position (Val1 only)
test "one"
3

Check out Get-Help about_Command_Syntax for all the gory details. :slight_smile: