Hello,
I have a CSV file that contains date 2016-11-10 00:00:00, the problem is that, it’s ignoring the 0 on the day (10
$Date_Effective = ($Import_CSV."Date Effective").Trim(" 00:00:00")
It’s reading 2016-11-10 as 2016-11-1
It was working fine yesterday since yesterday was 2016-11-09
Thank you,
Tony
Olaf
November 10, 2016, 1:48pm
2
try this:
$Date_Effective = ($Import_CSV."Date Effective").Trim("00:00:00").Trim()
… works for me
Thank you Olaf Soyk, that worked.
I know the second Trim() is to trim the 00:00:00, but how does the first Trim() work?
I would highly recommend if you are working with Dates to work with them as a date versus a string. Rather than trying to manipulate the string with Trims or replaces, convert it to a date and then you can format it however you want:
$date_as_string = "2016-11-10 00:00:00"
Get-Date $date_as_string -Format d
#or
Get-Date $date_as_string -Format "yyyy/MM/dd"
Output:
11/10/2016
2016/11/10
Olaf
November 10, 2016, 4:24pm
6
Of course Robs recommendation is always the best way. But to answer your question you can do this:
"'$('2016-11-10 00:00:00'.Trim('00:00:00'))'"
The Result will be '2016-11-10 '. There’s still a trailing space. That’s what the second Trim() removes:
"'$('2016-11-10 '.Trim())'"
The result will now be ‘2016-11-10’
Tony,
I often wish .Trim() worked like that, but it doesn’t.
$DateString.Trim( ’ 00:00:00’ ) is going to trim all spaces, colons and zeros that appear at the beginning and end of the string in any order.
The are many ways you could do what you want; I would probably do this:
$DateString.Split( ’ ’ )[0]
Olaf
November 10, 2016, 6:58pm
8
Tim,
wow … cool … thanks … now I really understand how the trim() operator works.
So if we would like to accomplish the task with the same approach we could even make it a little shorter:
“‘$(‘2016-11-10 00:00:00’.Trim(’0: ‘).trim())’”