37mm
1
I want to build a .txt file that has every file in a directory full path on each line.
ls | select name | Out-File test.txt
This is the contents test.txt
Name
----
jns22.txt
gps-position1.txt
gps-position2.txt
gps-position3.txt
gps-position6.txt
What I am looking for is the full path, and I don’t want the column header (Name).
Thanks in advance Fellas!
Does it have to be a txt file. Can it be a csv file?
37mm
3
No it doesn’t have to a txt file. Now that I think of it, a csv would fix my issue! I don’t think it will give me the full path of the file though.
ls | select -ExpandProperty FullName | Out-File test.txt
ls | select -Property FullName | Export-Csv test.csv
You will need to use Fullname instead of name. Try something like this:
(Get-ChildItem c:\ -Recurse).FullName | export-CSV c:\test.csv
Also this one:
Get-ChildItem c:\ -Recurse | out-file C:\Test\file.txt