# ActiveDirectory find all groups a user is member off **URL:** \ **Category:** PowerShell Help\ **Created:** [July 11, 2019, 5:25am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847 "2019-07-11T05:25:37Z")\ **Posts on this page:** 10\ **Page:** 1
**Author:** ![acer4605](https://avatars.discourse-cdn.com/v4/letter/a/13edae/32.png) [@acer4605](https://forums.powershell.org/u/acer4605)\ **Post date:** [July 11, 2019, 5:25am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/1 "2019-07-11T05:25:37Z")
Hi I can succesfully export a list from a given adgroup to csv ``` Get-AdGroupMember -identity "Office365" | select samaccountname |export-csv -path c:\output\office_teams_sam.csv -NoTypeInformation ``` now I want to use this list to search through AD to find other groups where they are member of only I don’t know how this is done can you help me out please   ---
**Author:** ![kvprasoon](https://sea1.discourse-cdn.com/flex019/user_avatar/forums.powershell.org/kvprasoon/32/4449_2.png) [@kvprasoon](https://forums.powershell.org/u/kvprasoon)\ **Post date:** [July 11, 2019, 6:08am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/2 "2019-07-11T06:08:03Z")
almost there, You can iterate through each element in CSV and do a Get-ADUser on each name with -Properties memberof ``` # below code inside Foreach Get-ADUser $CurrentUser.samaccountname -Properties memberof | Export-CSv -Path -NoTypeInformation ``` ---
**Author:** ![acer4605](https://avatars.discourse-cdn.com/v4/letter/a/13edae/32.png) [@acer4605](https://forums.powershell.org/u/acer4605)\ **Post date:** [July 11, 2019, 6:37am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/3 "2019-07-11T06:37:18Z")
Hi I still get an error here ``` $OfficeTeamsUser = Import-Csv -Path C:\output\office_teams_sam.csv foreach ($CurrentUser in $OfficeTeamsUser){ Get-ADUser $CurrentUser.SamAccountName -Properties memberof |Export-csv -path C:\Temp\output.csv -NoTypeInformation } ``` when I use samaccountname I get this error Get-ADUser : Cannot validate argument on parameter ‘Identity’. The argument is null. Provide a valid value for the argument, and then try running the command again. At line:3 char:12 - Get-ADUser $CurrentUser.SamAccountName -Properties memberof |Export-c … - ```auto ``` - CategoryInfo : InvalidData: (🙂 [Get-ADUser], ParameterBindingValidationException - FullyQualifiedErrorId : ParameterArgumentValidationError,Microsoft.ActiveDirectory.Management.Commands.GetADUser when I use $CurrentUser.name I get only 1 entry in my Csv   ---
**Author:** ![kvprasoon](https://sea1.discourse-cdn.com/flex019/user_avatar/forums.powershell.org/kvprasoon/32/4449_2.png) [@kvprasoon](https://forums.powershell.org/u/kvprasoon)\ **Post date:** [July 11, 2019, 7:15am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/4 "2019-07-11T07:15:14Z")
make sure there is a value in $CurrentUser.SamAccountname ---
**Author:** ![acer4605](https://avatars.discourse-cdn.com/v4/letter/a/13edae/32.png) [@acer4605](https://forums.powershell.org/u/acer4605)\ **Post date:** [July 11, 2019, 7:33am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/5 "2019-07-11T07:33:52Z")
I’ve got 1 column in my CSV with header and from row 2 all the users “SamAccountName” “dally”   by preference I would like to search through 5 different office groups (group 1 to 5) search for all the users in there. these need to be exported to a csv file with 1colum with the username and the second with all the groups he’s member of example “dally”,“Office365”, “Office365\_Admins” thanks for your help ---
**Author:** ![shawnwat](https://avatars.discourse-cdn.com/v4/letter/s/c67d28/32.png) [@shawnwat](https://forums.powershell.org/u/shawnwat)\ **Post date:** [July 11, 2019, 10:18am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/6 "2019-07-11T10:18:57Z")
I ran across this not too long ago. I don’t think this is the original post I used but should work: [https://techibee.com/active-directory/powershell-how-to-get-all-the-ad-groups-current-user-belongs/1672](https://techibee.com/active-directory/powershell-how-to-get-all-the-ad-groups-current-user-belongs/1672) ---
**Author:** ![lake](https://avatars.discourse-cdn.com/v4/letter/l/45deac/32.png) [@lake](https://forums.powershell.org/u/lake)\ **Post date:** [July 12, 2019, 2:24am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/7 "2019-07-12T02:24:28Z")
Hello, Is did like this, is this ok? This my first post, where I have included code, I hope this ok… ``` $result = @() $OfficeTeamsUsers = Get-AdGroupMember -identity "Office365" | select samaccountname foreach($user in $OfficeTeamsUsers) { $memberof = Get-ADUser $User.samaccountname -Properties memberof $table = New-Object psobject $table | Add-Member -NotePropertyName "samaccountname" -NotePropertyValue $User.samaccountname $table | Add-Member -NotePropertyName "memberof" -NotePropertyValue $memberof $result += $table $table = $null } $result | Export-CSv -Path C:\Temp\output.csv -NoTypeInformation ``` ---
**Author:** ![lake](https://avatars.discourse-cdn.com/v4/letter/l/45deac/32.png) [@lake](https://forums.powershell.org/u/lake)\ **Post date:** [July 12, 2019, 2:25am UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/8 "2019-07-12T02:25:25Z")
Hello, Is did like this, is this ok? This my first post, where I have included code, I hope this ok… ``` $result = @() $OfficeTeamsUsers = Get-AdGroupMember -identity "Office365" | select samaccountname foreach($user in $OfficeTeamsUsers) { $memberof = Get-ADUser $User.samaccountname -Properties memberof $table = New-Object psobject $table | Add-Member -NotePropertyName "samaccountname" -NotePropertyValue $User.samaccountname $table | Add-Member -NotePropertyName "memberof" -NotePropertyValue $memberof $result += $table $table = $null } $result | Export-CSv -Path C:\Temp\output.csv -NoTypeInformation ``` ---
**Author:** ![postanote](https://avatars.discourse-cdn.com/v4/letter/p/ebca7d/32.png) [@postanote](https://forums.powershell.org/u/postanote)\ **Post date:** [July 12, 2019, 7:28pm UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/9 "2019-07-12T19:28:04Z")
Don’t over think this. This is a very common daily thing. Really a PowerShell ADDS 101 thing. There are already pre-built scripts on the MS [powershellgallery.com](http://powershellgallery.com) for this use case and more. AS well as all over the internet. > https://www.powershellgallery.com/packages?q=%27group+member%27 > > See also: > > Find Circular Nested Groups > PowerShell script to find any instances of Circular Nested Groups in the domain. > > > **[Browse code samples](https://learn.microsoft.com/en-us/samples/browse/?redirectedfrom=TechNet-Gallery)** > > > > Get started with Microsoft developer tools and technologies. Explore our samples and discover the things you can build. > > Get nested group membership - function > This function will recursively enumerate members of a given group along with nesting level and parent group information. If there is a circular membership, it will be displayed in Comment column.It accepts input from pipeline and works well with get-adgroup. > [Browse code samples | Microsoft Learn](https://gallery.technet.microsoft.com/scriptcenter/Get-nested-group-15f725f2) It also could be as simple as this… ``` Get-ADUser userName –Properties MemberOf).MemberOf ``` Or even as simple as this… ``` Get-ADPrincipalGroupMembership username | select name ```   If you really want to get elegant about this… then see this… > http://vcloud-lab.com/entries/active-directory/powershell-active-directory-list-complete-hierarchy-of-upstream-nested-groups-recursively-of-user > > > **[Powershell Active Directory: Show treeview of User or Group memberof hierarchy](http://vcloud-lab.com/entries/active-directory/powershell-active-directory-show-treeview-of-user-or-group-memberof-hierarchy)** > > > > After going through many testing and successfully streamlining most of the Users and Groups member of in active directory environment using Powershell Active Directory: List complete hierarchy of u... > > [Powershell: List Active Directory group hierarchy](https://social.technet.microsoft.com/Forums/office/en-US/1fda5252-bd0f-4615-8238-cf08537b741f/powershell-list-active-directory-group-hierarchy)             ---
**Author:** ![dotnVo](https://avatars.discourse-cdn.com/v4/letter/d/4af34b/32.png) [@dotnVo](https://forums.powershell.org/u/dotnVo)\ **Post date:** [May 16, 2024, 8:32pm UTC](https://forums.powershell.org/t/activedirectory-find-all-groups-a-user-is-member-off/12847/10 "2024-05-16T20:32:00Z")